Final Answer
Step-by-step Solution
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Divide $x^2$ by $3+4x^2$
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$\begin{array}{l}\phantom{\phantom{;}4x^{2}+3;}{\phantom{;}\frac{1}{4}\phantom{;}\phantom{;}}\\\phantom{;}4x^{2}+3\overline{\smash{)}\phantom{;}x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{\phantom{;}4x^{2}+3;}\underline{-x^{2}\phantom{-;x^n}-\frac{3}{4}\phantom{;}\phantom{;}}\\\phantom{-x^{2}-\frac{3}{4}\phantom{;}\phantom{;};}-\frac{3}{4}\phantom{;}\phantom{;}\\\end{array}$
Learn how to solve problems step by step online. Find the integral int((x^2)/(3+4x^2))dx. Divide x^2 by 3+4x^2. Resulting polynomial. Expand the integral \int\left(\frac{1}{4}+\frac{-3}{4\left(3+4x^2\right)}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{1}{4}dx results in: \frac{1}{4}x.