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# Solve the quadratic equation $5x+2x^2-10=0$

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##  Final Answer

$x=1.311738,\:x=-3.811738$
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##  Step-by-step Solution 

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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=2$, $b=5$ and $c=-10$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-5\pm \sqrt{5^2-4\cdot 2\cdot -10}}{2\cdot 2}$

Learn how to solve quadratic equations problems step by step online.

$x=\frac{-5\pm \sqrt{5^2-4\cdot 2\cdot -10}}{2\cdot 2}$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 5x+2x^2+-10=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=2, b=5 and c=-10. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 10.246951 and -5.

##  Final Answer

$x=1.311738,\:x=-3.811738$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formulaFind break even pointsFind the discriminant

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

### Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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