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# Solve the equation $y=x^2+x+1$

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##  Final answer to the problem

$y=\left(x+\frac{1}{2}\right)^2+\frac{3}{4}$
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##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Differential
• Find the derivative
• Find the integral
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
Can't find a method? Tell us so we can add it.
1

Add and subtract $\displaystyle\left(\frac{b}{2a}\right)^2$

$y=x^2+x+1+\frac{1}{4}-\frac{1}{4}$

Learn how to solve equations problems step by step online.

$y=x^2+x+1+\frac{1}{4}-\frac{1}{4}$

Learn how to solve equations problems step by step online. Solve the equation y=x^2+x+1. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Factor the perfect square trinomial x^2+x+\frac{1}{4}. Subtract the values 1 and -\frac{1}{4}. The square root of \frac{1}{4} is .

##  Final answer to the problem

$y=\left(x+\frac{1}{2}\right)^2+\frac{3}{4}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Equations

In mathematics, an equation is a statement of an equality containing one or more variables. Solving the equation consists of determining which values of the variables make the equality true. In this situation, variables are also known as unknowns and the values which satisfy the equality are known as solutions.