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Integrate (16-1x^2)^0.51/8(16-1x^2)*-1 from 0 to 4

\int_{0}^{4}\left(\sqrt{16-x^2}-\frac{1}{8}\cdot\left(16-x^2\right)\right)dx

Step by step solution

Problem

$\int_{0}^{4}\left(\sqrt{16-x^2}-\frac{1}{8}\cdot\left(16-x^2\right)\right)dx$

Show full step-by-step solution

Answer

$\int_{0}^{4}\frac{d}{d\theta}\left(4\sin\left(\theta\right)\right)\cos\left(\theta\right)d\theta-\frac{16}{3}$

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$\int_{0}^{4}\left(\sqrt{16-x^2}-\frac{1}{8}\cdot\left(16-x^2\right)\right)dx$

Main topic:

Integration by trigonometric substitution

Used formulas:

4. See formulas

Time to solve it:

0.44 seconds