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\int_{0}^{4}\left(\sqrt{16-x^2}-\frac{1}{8}\cdot\left(16-x^2\right)\right)dx

Integrate (16-1x^2)^0.51/8(16-1x^2)*-1 from 0 to 4

Answer

$-\frac{17}{\sqrt{3}}$

Step-by-step explanation

Problem

$\int_{0}^{4}\left(\sqrt{16-x^2}-\frac{1}{8}\cdot\left(16-x^2\right)\right)dx$
1

Multiply $-1$ times $\frac{1}{8}$

$\int_{0}^{4}\left(\sqrt{16-x^2}-\frac{1}{8}\left(16-x^2\right)\right)dx$

Unlock this step-by-step solution!

Answer

$-\frac{17}{\sqrt{3}}$