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Step-by-step Solution

Integrate $\sqrt{16-x^2}-1\left(\frac{1}{8}\right)\left(16-x^2\right)$ from $0$ to $4$

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Answer

$-5.1937$

Step-by-step explanation

Problem to solve:

$\int_{0}^{4}\left(\sqrt{16-x^2}-\frac{1}{8}\cdot\left(16-x^2\right)\right)dx$
1

Multiply $-1$ times $0.125$

$\int_{0}^{4}\left(\sqrt{16-x^2}-\frac{1}{8}\left(16-x^2\right)\right)dx$
2

The integral of a sum of two or more functions is equal to the sum of their integrals

$\int_{0}^{4}\sqrt{16-x^2}dx+\int_{0}^{4}\left(-2+\frac{1}{8}x^2\right)dx$

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Answer

$-5.1937$