Try now NerdPal! Our new app on iOS and Android

# Find the integral $-\int_{\infty }^{\frac{27}{50}\cdot e^{-1101}}\frac{1153}{500}\cdot e^{-1381}\frac{1}{r^2}dr$

Go!
Math mode
Text mode
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

0

##  Step-by-step Solution 

Problem to solve:

$-\int_{\infty }^{\frac{27}{50}\cdot e^{-1101}}\frac{1153}{500}\cdot e^{-1381}\frac{1}{r^2}dr$

Specify the solving method

1

Simplifying

$-\int_{\infty }^{\frac{27}{50}\cdot e^{-1101}}2.306\cdot e^{-1381}\left(\frac{1}{r^2}\right)dr$

Learn how to solve integral calculus problems step by step online.

$-\int_{\infty }^{\frac{27}{50}\cdot e^{-1101}}2.306\cdot e^{-1381}\left(\frac{1}{r^2}\right)dr$

Learn how to solve integral calculus problems step by step online. Find the integral -int(1153/500e^(-1381)1/(r^2))dr&infinity&27/50e^(-1101). Simplifying. Simplify the expression inside the integral. The integral of a constant is equal to the constant times the integral's variable. Any expression multiplied by 0 is equal to 0.

0

### Main topic:

Integral Calculus

~ 0.04 s

###  Join 500k+ students in problem solving.

##### Without automatic renewal.
Create an Account