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# Find the integral $-\int_{\infty }^{\frac{27}{50}\cdot e^{-1101}} e^{-1381}\frac{1153}{500}\frac{1}{r^2}dr$

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## Step-by-step Solution

Problem to solve:

$w=-\int_{\infty}^{\frac{27}{50} e^{1101\left(-1\right)}}\frac{1153}{500} e^{1381\left(-1\right)}\cdot\frac{1}{r^2}dr$

Specify the solving method

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Simplifying

$-\int_{\infty }^{\frac{27}{50}\cdot e^{-1101}}2.306e^{-1381}\left(\frac{1}{r^2}\right)dr$

Learn how to solve integral calculus problems step by step online.

$-\int_{\infty }^{\frac{27}{50}\cdot e^{-1101}}2.306e^{-1381}\left(\frac{1}{r^2}\right)dr$

Learn how to solve integral calculus problems step by step online. Find the integral -int(1153/500e^(-1381)1/(r^2))dr&\infty&27/50e^(-1101). Simplifying. Simplifying. The integral of a constant is equal to the constant times the integral's variable. Replace the integral's limit by a finite value.

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$w=-\int_{\infty}^{\frac{27}{50} e^{1101\left(-1\right)}}\frac{1153}{500} e^{1381\left(-1\right)}\cdot\frac{1}{r^2}dr$

### Main topic:

Integral Calculus

~ 0.04 s