Final Answer
0
Step-by-step Solution
Problem to solve:
$w=-\int_{\infty}^{\frac{27}{50} e^{1101\left(-1\right)}}\frac{1153}{500} e^{1381\left(-1\right)}\cdot\frac{1}{r^2}dr$
Specify the solving method
1
Simplifying
$-\int_{\infty }^{\frac{27}{50}\cdot e^{-1101}}2.306e^{-1381}\left(\frac{1}{r^2}\right)dr$
Learn how to solve integral calculus problems step by step online.
$-\int_{\infty }^{\frac{27}{50}\cdot e^{-1101}}2.306e^{-1381}\left(\frac{1}{r^2}\right)dr$
Learn how to solve integral calculus problems step by step online. Find the integral -int(1153/500e^(-1381)1/(r^2))dr&\infty&27/50e^(-1101). Simplifying. Simplifying. The integral of a constant is equal to the constant times the integral's variable. Replace the integral's limit by a finite value.
Final Answer
0