Final Answer
$\frac{6^{\left(1-n\right)}}{{\left(-2\right)}^{\left(3-2n\right)}}$
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Step-by-step Solution
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The limit of a constant is just the constant
$\frac{6^{\left(1-n\right)}}{{\left(-2\right)}^{\left(3-2n\right)}}$
Final Answer
$\frac{6^{\left(1-n\right)}}{{\left(-2\right)}^{\left(3-2n\right)}}$