$9-x=15$
$3x^2-x-1$
$\frac{4x-7}{6x^2+13x-5}$
$\frac{x^2-81}{x+9}$
$\lim_{x\to\infty}\left(-2x-3\right)$
$\lim_{x\to-\infty}\left(\frac{2.5x^3-6x^2+x+6}{x^2+x-5}\right)$
$\int\frac{9x+4}{\left(18x^2+16x\right)^5}dx$
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