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Exercise

$rational\left(i r^2\cdot x\sqrt{y}\right)$

Step-by-step Solution

1

Apply the formula: $rational\left(a\right)$=true, where $a=ir^2x\sqrt{y}$

true

Final answer to the exercise

true

Try other ways to solve this exercise

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  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Prove from LHS (left-hand side)
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Similar Questions Solved

$rational\left(\frac{1+irational\left(\sqrt{3}\right)}{18}\right)$

$rational2.1331333133331$

$rational7.466446644$

$rational1.4300$

$irrational2.1331333133331$

$irrational1.41352897$

$irrational\:\sqrt[3]{6125}$

Main Topic: Rationals and Irrationals

A rational term is an algebraic term that doesn't have literal part inside a radical. An irrational term does have literal part inside a radical.

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