$100-400+30$
$4x^2+14x+12=0$
$\frac{dy}{dx}=\frac{2x}{3y^4}$
$16x^2-36=0$
$\left(2x^2-3x+5\right)-\left(x^3-2x+2\right)$
$\int\frac{x\left(1-x\right)}{1+\left(x\right)^2}dx$
$\frac{d}{dx}\frac{e^x}{5x+4}$
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