$\frac{dy}{dx}=1-xy$
$\frac{-2}{x^2+2}=\frac{2}{x-4}$
$\int\left(4x\sqrt[3]{x^2+6x+9}\right)dx$
$3y^2+9y-27$
$\left(\frac{1}{3}x^2+\frac{1}{4}y^2\right)^2$
$f\left(x\right)=\sin\left(x^2+\cos\left(x\right)\right)$
$3\sqrt{6}\cdot4$
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