$4x^2-12x+5$
$6x^2+11x+3=0$
$3x-4=2x+6$
$2^2-6\cdot1+9$
$\frac{6+12}{2}$
$\lim_{x\to4}\left(\frac{\sqrt[3]{x+8}-2}{\sqrt[4]{x+21}-3}\right)$
$\int_0^4\left(3xe^{-x}\right)dx$
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