$x-5\ge12$
$100x^2+26x$
$\sqrt[3]{a^2b}+\frac{1}{3}\sqrt[6]{a^4b^2}+\frac{4}{3}\sqrt[12]{a^8b^4}$
$13x-21>5-x$
$\frac{dy}{dx}=\frac{1}{15}y\left(5-y\right)$
$-50\left(x+g\right)^3$
$\left(a^{x+1}+a^{x-2}\right)^2$
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