$\tan\left(x+\left(\frac{3\pi}{2}\right)\right)=-\cot\left(x\right)$
$\frac{1-\sin^2x}{\sin x}$
$16x^2+16x+4$
$\frac{1}{2}\cdot\sin\left(x\right)+1-\cos^2\left(x\right)=0$
$\lim_{x\to0}\left(\frac{3^{cosx}-3}{4x}\right)$
$cot\left(x\right)tan^2\left(x\right)+cot\left(x\right)$
$3y-8=-2$
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