$\frac{\left(1+cscx\right)}{secx}=cosx+cotx$

$15a^2b^3.5a^2\:b^5\cdot$

$arccos\left(cos\frac{3\pi}{2}\right)$

$\frac{3}{x+2}+\frac{2}{x}+\frac{6}{x+4}$

$x^2-16x+48$

$\sin\left(x\right)-\sin\left(x\right)^3=\sin\left(x\right)\cos\left(x\right)^2$

$\int\:\left(\frac{1}{x^2+2x+3}\right)dx$