$\left(4x^3-2y^3\right)^2$
$10a^2+30a+40=a^2-6a+4$
$\lim_{x\to0}\left(4+x^{3lnx}\right)$
$\frac{2x+16}{4}$
$\:\left(7x^2\:-\:4x^9\right)\:\left(7x^2\:+\:4x^9\right)$
$a^2+7a+12=0$
$-1\left(-4\right)\left(-4\right)\left(-3\right)$
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