$\int\frac{\sqrt{4x^2+8}}{x}dx$
$9+2.5^2$
$\frac{x^2}{4}+4y^2$
$\left(\frac{3}{4}a-2b\right)^2$
$\left|-3\right|\cdot\left|-2+8\right|$
$7\sqrt{450}$
$4b^2-16c^4\:$
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