$5^3x\:5^4$
$\left(3a+b\right)^2+3\left(a+b\right)^2$
$\frac{d}{dx}x^3.y^2=2x^2+y^2$
$\frac{x^5-x^4+x^2-9}{x^2+1}$
$14\cdot\left(-15\right)$
$\left(\frac{1}{x^2}-\frac{3}{x^4}\right)\left(x+5x^3\right)$
$6a+7x-10a+3a-8x$
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