$6x^3\:4x^3\:5x^3$
$\int\:\frac{x\cdot\:\:x}{\left(x-3\right)\left(x^2+4\right)}$
$\frac{1}{4}x^2-7x+8+3x$
$v=\left(29.7-2x\right)\left(21.6-2x\right)x$
$\int_0^6\frac{-2x+14}{3}dx$
$\left(12a-7b\right)\left(7b+12a\right)$
$-2\:x\:-1\:x\:5$
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