$x^3y'+2x^2y-12=0$
$\left(2x+3\right)^2,\:x=4$
$-7+w=7$
$\frac{1}{2^{-2}}$
$\int_{-1}^1\left(3x^{-4}\right)dx$
$ty'+4y=0$
$\frac{dy}{dt}=kt^2y$
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