$\int\frac{sec\left(x\right).\tan\left(x\right)}{\sqrt{\sec^2\left(x\right)+1}}dx$

$\frac{\left(6x^4^4-15x^3+8x-15\right)}{\left(2x-5\right)}$

$\left(\frac{2}{3}\right)^{10\:}\:\left(\frac{2}{3}\right)^{-10}$

$5m+3t-4m-t$

$\frac{dy}{dx}=8y\left(x^{-2}\right)$

$x^3\cdot\frac{x^{-2}}{x^5}$

$6f-7m\cdot6f+8m$