$\lim_{x\to0}\left(\frac{ln\left(x\right)}{x^2+2}\right)$
$\int_0^2v\left(u\right)du$
$\left(-46\right)-\left(-17\right)$
$\sin2x=-\frac{8}{9}$
$\lim\:_{x\to\:\infty\:}\left(\frac{-3cos\left(x\right)+5x^2-2x+7}{3cos\left(x\right)+2x^2+5x-7}\right)$
$\left(x+10\right)\left(x-5\right)$
$4sen2\left(x\right)=1$
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