$\left(3m-2m^2\right)^3$
$\frac{d}{dx}2x+3$
$\left(3m^4+6\right)\left(3m^4-6\right)$
$60-4x=x^2$
$\lim_{x\to\infty}\left(\frac{24x^2-5x-10}{-4x^2+10x-8}\right)$
$7.6x\:+\:4.8x$
$x^2-x\:=2x+4$
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