$\frac{dy}{dx}+\frac{2x}{1+x^2}\left(y\right)=\frac{1}{\left(1+x^2\right)^2}$
$y=5y$
$\left(1-2\right)\cdot3^2$
$tan\theta\:+cos\theta\:=sec\theta\:\cdot csc\theta\:$
$5x+2y=4$
$\frac { ( 1 - x ) ^ { 3 } } { x ^ { 3 } }$
$10\cos\:c+1=\cos\:c-1$
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