$\frac{\left(x^2+4\right)\left(x-2\right)}{\left(3x+6\right)\left(x+2\right)}$
$x^2\left(x^2-2x+1\right)^2$
$\left(a^2+\frac{3}{5}\right)\left(a^2-\frac{3}{5}\right)$
$\left(x-1\right)^2\left(x-3\right)$
$z^3+z+xy=1$
$5\:x\:\left(-2\right)^3$
$2g^2-144h^2$
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