$-8-\left(-15\right)-17+\left(3\right)$
$x^2+11x+18\le\:0$
$-\frac{2}{3}x^3y-\frac{1}{6}x^3y-\frac{1}{9}x^3y-\frac{1}{12}x^3y$
$x+6\left(x-2\right)$
$3x+4-1$
$4abc+17abd-3abc+5abc-7abd$
$\frac{dy}{dx}=\:\frac{1}{x^2\left(8+9y^2\right)}$
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