$-2x-\frac{2}{3}x$
$-\left(4x+9y+7\right)$
$10x^2+9=x$
$\int\left(\left(3x^6+5x-8\right)\left(18x^5+5\right)\right)dx$
$\int\left(\frac{7\arctan\left(x\right)}{\:1+x^2}\right)dx$
$\frac{2}{x^2-1}+\frac{x}{x-1}-\frac{x}{x-1}$
$x-3=17$
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