$\frac{1+\sec\left(x\right)}{\tan\left(x\right)}=\frac{1}{\tan\left(x\right)}$

$6ab-2ab2+6ab2+7ab2+ab2\:8ab2-11ab2+2ab2\:$

$y'=x-xy$

$4\ln\left(4x\right)-2\ln\left(x\right)=3$

$9n-3+9n+3$

$3^4\cdot3^{-1}$

$\left(-\frac{148}{31200}\right)+\left(\frac{83.5}{3307.5}\right)+\left(\frac{50.5}{1575}\right)+\left(\frac{16}{360}\right)+\left(\frac{62}{985.359375}\right)+\left(-\frac{3}{2450}\right)+\left(+\frac{2}{11088}\right)$