$x^2-9=6x$
$5\left(x-3\right)\ge2\left(x+3\right)$
$x\left(9x-1\right)$
$3\:\left(2x-4+x\right)$
$\lim_{x\to0}3\left(\frac{1}{x}-cscx\right)$
$\int_0^x\left(\frac{1}{1-x}\right)dx$
$\frac{4x+3}{2}+\frac{3x-4}{3}$
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