$\sqrt{3x}+\sqrt[3]{4y}=5$
$\left(-8\right)\:x\:4\:x\:\left(-2\right)$
$-13\:+\:9\:+\:-1$
$\frac{1}{6}\int6\left(x-1\right)\left(3x^2-6x+1\right)^5dx$
$\left(-x\right)^3-\:\left(-x\right)^0$
$\int\frac{x+1}{3x^2+6x-3}dx$
$2x^2y^2+x^2+y^2-5,\:x=0,\:y=0$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!