$\frac{dy}{dx}=\frac{y}{1+x}^2$
$\left[4a^2+4b^2\:\right]^2$
$\int_{\frac{-\pi}{2}}^{\frac{\pi}{4}}\left(\frac{\sqrt{2}\sin\left(4x\right)}{\sqrt{1-\cos\left(4x\right)}}\right)dx$
$\int\left(\frac{\left(x^4\right)}{x^5-4}\right)dx$
$\left(\frac{-x+6x^2}{3x^3+4x}\right)^3$
$\frac{d}{dx}\left(\frac{8x+13}{15x^2+7}\right)^6$
$-x^2+6x-8=0$
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