$\lim_{x\to1}\sin\left(\frac{\sqrt{x+1}}{x^2-1}\right)$
$32.587\:+\:369.877\:+\:1.011\:$
$\frac{2}{5}n+6=10$
$\frac{\left(4h^4\right)^3}{2h^5}$
$63.45+14.33$
$8^3x\:8^9$
$\frac{2x}{3}-\frac{5}{2}=\frac{x}{4}$
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