$\infty+75$
$\frac{140ab^5c^3}{20ab^2c}$
$5x-6y+2x$
$512+128-8+3$
$\frac{12n^2}{4n^3}$
$12-2\left(5-3x\right)=4\left(x+3\right)$
$\left(2\right)\left(-2\right)\left(2\right)\left(-2\right)\left(2\right)\left(-2\right)\left(2\right)$
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