$5x+6\ge8x-12$
$\int\frac{1}{x^2\left(x+4\right)}dx$
$5x^2\left(x^2-3x+8\right)$
$-\left[-\left(-1\right)+\left(2+-3\right)\right]$
$3x-\frac{3}{4}<0$
$\int sin\left(x\right)\cdot\left(2x+5\right)dx$
$\:-2x+10=2\:\left(x-5\right)$
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