$36+21c^2-132c$
$\lim_{x\to\infty}\left(\left(\frac{\left(3x-1\right)}{4x+2}\right)^{-5+x}\right)$
$\left(2x+1\right)^2=4x$
$-9-\left(2-9\right)$
$\frac{x^2}{3}-4=0$
$xy^2-xz^2$
$\ln\left(y-1\right)-\ln\left(x\right)=x+\ln\left(x\right)$
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