$\int\left(-4x^{-10}+3x^8-9\right)dx$
$\int\frac{a}{b-cx}dx$
$x^4-3x^2+4$
$27-58$
$\left(2abc-8d^4\right)^3$
$\frac{1}{3}\left(\frac{13}{4}-1\right)^{\frac{3}{2}}=\frac{9}{8}$
$\frac{x^3-16x}{x^2-4}$
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