$\frac{960}{16}$
$2x\left(-10x^3\right)$
$7b\left(2a-b\right)$
$\left(28+16\right)+12+y$
$\left(6\right)^3+\left(6\right)^4<6^5$
$3x+3y+12z=6$
$\int\frac{x^3+3x-2}{x^2-x}dx$
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