$\int_{-1}^2\left(xe^{-x}\right)dx$
$\lim_{x\to-1}4x^2$
$\left(2+\left(x^2+1\right)^4\right)^3$
$\lim_{x\to3}\frac{\left(2x^2-18\right)}{3-x}$
$y'=\frac{1}{\left(x-6\right)^8}$
$\frac{4x^2+4x}{x^2-1}$
$ab+5ab^2$
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