$\left(1045\right)\left(1014\right)$
$x^2+10x+12=0$
$-4x-2x$
$\frac{\tan\left(x\right)-\sec\left(x\right)}{\sin\left(x\right)-1}=\sec\left(x\right)$
$\frac{dy}{dt}+10y=15,y\left(0\right)=0$
$\left(4v+m\right)^5$
$\frac{dy}{dx}=\frac{y+4}{x-3}$
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