$\left(2x+3\right)^2-\left(4y-5\right)^2$
$\left(5mu\right)^3$
$\frac{\cot\:\theta\:}{cos\theta\:}$
$-24:12$
$\left(3x^2+4x\right)\left(3x-5\right)$
$x\:+\:6\:-\:11x\:+\:y\:-\:10$
$5+x<2x+4$
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