$\frac{dy}{dx}\tan\left(2y\right)=x+\sec\left(x\right)$

$4x^2+y^2-36=0$

$\frac{1}{4}ab+\frac{1}{2}ab+\frac{1}{3}ab$

$\left(-3\right)\cdot\left(26+92\right)-\left(-8\right)\cdot\left(-3\right)$

$\lim_{x\to\infty}\left(\frac{x^3}{e^{.01x}}\right)$

$\lim_{x\to\infty}\left(\frac{ln\left(x\right)}{x^2+x}\right)$

$\lim_{x\to0}\frac{\sqrt{x^2+5}-3}{x^2-4}$