$x+12\le3x$
$\frac{2x^3+10x^2+16x+8}{4x^3+8x^2-4x-8}$
$x\left(x-1\right)-4\left(x-1\right)$
$1055+100-05$
$64x\left(2\right)-48xy+8y\left(2\right)$
$x^2+2x-8x$
$2x-y+2x+3xy$
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