$\frac{dy}{dx}=\cos\left(x+1\right)$
$\frac{x^3-6x^2+4x-19}{x-3}$
$y^3\sqrt{3}-y^2\:$
$f\left(x\right)=\sin^{-1}\left(x\right)\left(3x+1\right)$
$\frac{1}{9}x\frac{4}{12}$
$-10x-10>=60$
$\left(-2\sqrt{6}\right)^2$
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