Simplifying
$\frac{x^2-1}{x^2+3x+2}=2$
$\frac{2x+3y}{2x+3y}$
$\left(-\frac{6x^{5}y^{4}}{c^{4}}\right)^{5}$
$30+37.45$
$\int\frac{1}{\left(5x-1\right)\left(\ln\left(5x-1\right)\right)}dx$
$\log\left(4\right)+\log\left(5x\right)=2$
$\lim_{x\to\infty}\left(\frac{2x^2-x+1}{3x+5}\right)$
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