$32a^3b+24ab^2+16abc$
$\left(-\infty\right)^2-6\left(-\infty\right)$
$4m^2-3m-4=0$
$\int\frac{6x+12}{x^2+3x}dx$
$\int\left(2x+7\right)^7dx$
$\left(2x+3\right)^2-\left(x+4\right)^2-3\left(x+1\right)^2$
$\left(3x^3-4\right)\left(3x^3+20\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!