$1-25x^6y^6$
$x^2+12x=-20$
$\frac{3}{5x-6}\le\:-2$
$\lim_{x\to\infty}\left(\frac{1-\cos\left(x\right)}{x^2+x}\right)$
$-\int\frac{1}{x^3}\sqrt{1-\frac{2}{x^2}}dx$
$\sqrt[3]{130-5}$
$\frac{3^{-20}}{3^{-5}}$
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