$\frac{x^3+6x-2}{x-1}$
$-\:50x\:-\:30$
$xcos^2\left(y\right)dx+tan\left(y\right)dy=0$
$3x-\frac{5}{6}>3$
$\left(-2xy+3x-4y\right)\left(5y+2x-6y^2\right)$
$\frac{3x^3-10x^2+17x}{x-3}$
$\left(\frac{1}{4}x-3\right)^2$
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