$\frac{5x^3-14x+3}{x-2}$
$\frac{d}{dx}\left(\log\left(\frac{9}{2}\right)\right)$
$\left(3x-1\right)\left(2-x\right)$
$5y+1=6$
$y'=\frac{-x}{y-2}$
$\lim_{x\to0}\left(\frac{1+\cos\left(x\right)}{\tan\left(x\right)^2}\right)$
$\left(4a\:-\:2b\right)^2$
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