$\left(4^{3\left(0\right)}\right)$
$-5^2+2\cdot8+8^2$
$\:\:\:\frac{1}{4}\int_0^4tdt$
$-\left(\frac{1}{3}\right)e^{\left(-3y\right)}=c$
$3\cdot39$
$15ab+3a^2b^3-9a^3b^2$
$f^3-11f^2+f-11$
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