$\int\left(6x^2\right)\left(x^3+8\right)^{10}dx$
$4.24\left(10^0\right)$
$32\cdot2$
$\left(6x^2-3x\right)\cdot\left(x^2+2\right)-\left(2x^2+1\right)\cdot\left(x^2-4\right)$
$\frac{c^7}{c^{-1}}$
$\frac{\cos\left(a\right)}{\sin\left(b\right)}-\frac{\sin\left(a\right)}{\cos\left(b\right)}$
$5z-4z$
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