$\lim_{x\to\frac{1}{2}}\left(\frac{8x^3-1}{2x-1}\right)$
$\left(-8\right)\left(-x-2\right)$
$\frac{3x^2-1}{x^3-3}$
$\left(x+7y\right)\left(x-7y\right)$
$8x^2+2y^2-16x+8y+14=0$
$3+-6^2+\left(-2^4\right)$
$2\left(2x^2+2x-24\right)$
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